Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 5 - Exercises and Problems - Page 92: 64

Answer

Please see the work below.

Work Step by Step

We know that $\omega=\sqrt{\frac{g}{r}}$..........eq(1) Let x be the revolutions per minute required to simulate earth's gravity. Then radians per second conversion gives us $\omega=\frac{x\times 2\pi}{60}$...........eq(2) comparing eq(1) and eq(2), we obtain: $\frac{x\times 2\pi}{60}=\sqrt{\frac{g}{r}}$ This can be rearranged as: $x=\frac{60}{2\pi}\times \sqrt{\frac{g}{r}}$ We plug in the known values to obtain: $x=\frac{60}{2\times 3.1416}\sqrt{\frac{9.8}{\frac{450}{2}}}$ $x=1.99\space revolutions \space \space per\space minute$
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