## Essential University Physics: Volume 1 (4th Edition)

We know that the force of friction should be equal to the weight of the bat that is $F_{friction}=F_{gravity}$ $\implies \mu n=mg$ $\mu (ma)=mg$ This simplifies to: $a=\frac{g}{\mu}$ $a=\frac{9.8}{0.86}=11\frac{m}{s^2}$