Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 5 - Exercises and Problems - Page 92: 52

Answer

Please see the work below.

Work Step by Step

We know that the force of friction should be equal to the weight of the bat that is $F_{friction}=F_{gravity}$ $\implies \mu n=mg$ $\mu (ma)=mg$ This simplifies to: $a=\frac{g}{\mu}$ $a=\frac{9.8}{0.86}=11\frac{m}{s^2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.