Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 5 - Exercises and Problems - Page 92: 57


Please see the work below.

Work Step by Step

We know that the frictional force is given as: $f=\mu N$ $\implies f=\mu (0.7M)g$ To find out the maximum acceleration, we equate this to $Ma$ $\implies \mu(0.7M)g=Ma$ This simplifies to: $a=\mu(0.7)g$ We plug in the known values to obtain: $a=(0.61)(0.7)(9.8)$ $a=4.2\frac{m}{s^2}$
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