Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 4 - Exercises and Problems - Page 71: 48

Answer

Please see the work below.

Work Step by Step

(a) We know that $a=\frac{v}{\Delta t}$ Hence, the force is given as $F=ma=\frac{mv}{\Delta t}$ (b) We know that the acceleration is given as $a=\frac{v^2}{2\Delta x}$ Hence, the force is given as $F=ma=\frac{mv^2}{2\Delta x}$
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