Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 4 - Exercises and Problems - Page 71: 42

Answer

$1218.84\space N$

Work Step by Step

Please see the image first. Let's apply equation $F=ma$ to Martian. $\uparrow F=ma$ $R-84g=84\space kg\times10.8\space m/s^{2}$ $R-84kg\times3.71\space m/s^{2}=907.2\space N$ $R=907.2\space N+311.64\space N$ $R=1218.84\space N$
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