Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 4 - Exercises and Problems - Page 71: 40

Answer

$10290.15\space N$

Work Step by Step

Please see the image first. Let's apply the equation $F=ma$ to the elevator. $\uparrow F=ma$ Let's plug known values into this equation. $T-975g= 975\space kg\times0.754\space m/s^{2}$ $T=10290.15\space N$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.