## Essential University Physics: Volume 1 (4th Edition)

We find the value of t: $\Delta y = v_0t + \frac{1}{2}at^2$ $5300 = 132.2t + \frac{1}{2}(4.6)t^2$ $0 = -5300+ 132.2t + 2.3t^2$ $\fbox{t=27.21 seconds}$