Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 2 - Exercises and Problems - Page 32: 80

Answer

27.21 seconds

Work Step by Step

We find the value of t: $\Delta y = v_0t + \frac{1}{2}at^2 $ $5300 = 132.2t + \frac{1}{2}(4.6)t^2 $ $0 = -5300+ 132.2t + 2.3t^2 $ $\fbox{t=27.21 seconds}$
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