Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 2 - Exercises and Problems - Page 32: 66

Answer

a) 21.3 meters per second b) 2.6 seconds

Work Step by Step

a) We simplify the equation for final velocity in order to find the initial velocity: $v_0 = \sqrt{v_f^2 - 2a\Delta x}$ $v_0 = \sqrt{5^2 - 2(-6.3)(34)}=\fbox{21.3 meters per second}$ b) We find the change in time: $t = \frac{5-21.3}{-6.3}=\fbox{2.6 seconds}$
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