Answer
Please see the work below.
Work Step by Step
We know that the distance traveled by each car is
$d=\frac{v^2}{2a}$
We plug in the known values to obtain:
$d=\frac{(\frac{88}{3.6})^2}{2(8)}=37.3m$
and the total displacement of the two cars is
$d^{\prime}=2d=2(37.3)=75m$
and the distance between the cars is
$D=85-74.6=10m$
