Answer
290 K
Work Step by Step
Using the fact that $P^{1- \gamma} \times T^ {\gamma}$ remains constant, we find:
$T_2=T_1 (\frac{P_1}{P_2})^{1/ \gamma -1}$
We plug in the given values to obtain:
290 K
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 18 - Exercises and Problems - Page 344: 83
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