Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 18 - Exercises and Problems - Page 344: 83

Answer

290 K

Work Step by Step

Using the fact that $P^{1- \gamma} \times T^ {\gamma}$ remains constant, we find: $T_2=T_1 (\frac{P_1}{P_2})^{1/ \gamma -1}$ We plug in the given values to obtain: 290 K
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