## Essential University Physics: Volume 1 (4th Edition)

We know that: $\frac{P_1}{P_2}= \frac{V_2}{V_1}^ \gamma$ $\frac{V_2}{V_1}= \frac{P_1}{P_2}6 \gamma$ Plugging in the known values gives the ratio as: .7485 Thus, the pressure decreases by less than 50%.