Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 18 - Exercises and Problems - Page 344: 82

Answer

The pressure decreases by less than 50%.

Work Step by Step

We know that: $ \frac{P_1}{P_2}= \frac{V_2}{V_1}^ \gamma$ $ \frac{V_2}{V_1}= \frac{P_1}{P_2}6 \gamma$ Plugging in the known values gives the ratio as: .7485 Thus, the pressure decreases by less than 50%.
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