Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 18 - Exercises and Problems - Page 341: 22

Answer

216 K

Work Step by Step

We know that: $\frac{T_2}{T_1} = { (\frac {V_1}{V_2})}^{ \gamma -1}$ We know that the volume is cut by a factor of 4 and that $\gamma$ is equal to 1.4. This gives: $T_2= (\frac {4}{1})^{.4} \times 291 K$ We know: $\Delta T = T_2-T_1=216 K$
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