Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 18 - Exercises and Problems - Page 341: 14

Answer

Please see the work below.

Work Step by Step

We know that $\frac{dU}{dt}=\frac{dQ}{dt}+\frac{dW}{dt}$ This can be rearranged as: $\frac{dQ}{dt}=\frac{dU}{dt}-\frac{dW}{dt}$ We plug in the known values to obtain: $\frac{dQ}{dt}=45-165$ $\frac{dQ}{dt}=-120W$
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