Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 18 - Exercises and Problems - Page 341: 17

Answer

$W = 2p_1V_1$

Work Step by Step

We know that: $ W = \int p dV$ The area under the curve going from A to C is 0, so the gas does no work. We then find the work involved in going from C to B, which is given by the rectangular area under the curve. $ W = (2p_1-0)*(2V_1-V_1)$ $W = 2p_1V_1$
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