Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 17 - Exercises and Problems - Page 324: 19

Answer

Please see the work below.

Work Step by Step

We know that the latent heat is given as $L=\frac{Q}{m}$ We plug in the known values to obtain: $L=\frac{200}{0.008}$ $L=25000\frac{J}{Kg}$ $L=25\frac{KJ}{Kg}$ Thus, the sample is lead.
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