Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 17 - Exercises and Problems - Page 324: 16


Please see the work below.

Work Step by Step

We know that $PV=nRT$ This can be rearranged as: $n=\frac{PV}{RT}$ We plug in the known values to obtain: $n=\frac{(10^{-10})(0.001)}{(8.314)(273.15)}$ $n=4.403\times 10^{-17}moles$ Now we can find the number of molecules as $N=nN_A$ $N=(4.403\times 10^{-17})(6.022\times 10^{23})$ $N=2.7\times 10^7 molecules$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.