## Essential University Physics: Volume 1 (4th Edition) Clone

Recall that $H_2$ weights $3.3 \times 10^{-27}$ kg, and Sulfur Dioxide weighs $1.1 \times 10^{-25}$ kg. Thus: $v_ = \sqrt{\frac{3(T)}{m}}$ For Hydrogen: $v = \sqrt{\frac{3(1.4 \times 10^{-23})(75)}{3.3 \times 10^{-27}}} = 967 m/s$ For Sulfur Dioxode: $v = \sqrt{\frac{3(1.4 \times 10^{-23})(350)}{1.1 \times 10^{-25}}} = 370 m/s$