## Essential University Physics: Volume 1 (4th Edition)

We have to find the ratios between the two heights, which we will call $h_1$ and $h_2$. Thus, we find: $\frac{h_2A\rho_wg}{h_1A\rho_wg}=\frac{3mg}{mg}$ Thus, we see that the ratio is 3 to 1. This means that the minimum depth is: $h= 9(3)=27m$