Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 15 - Exercises and Problems - Page 290: 46


$8.6 \ MPa$

Work Step by Step

We know that pressure is equal to force over area. Thus, we find: $ P = \frac{5.6\times10^3N}{\pi \times (.025^2)}= 2.85\ MPa$ We multiply this by 1.5 to account for the extra pressure it can withstand, and then we divide by 1/2 to find: $ \frac{2.85 \times 1.5}{.5}=8.6 \ MPa$
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