## Essential University Physics: Volume 1 (4th Edition)

We find the force on the dam: $F = \int_0^H (\rho gbh)dh \\ F = .5\rho gbh^2$ Plugging in the known values, it follows: $F=.5(1000)(9.81)(1500)(95^2) = 66.4 \ GN$ We find: $\frac{100}{66.4} = 1.51$ This is greater than 1.5 times the force, so the dam is fine.