Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 14 - Exercises and Problems - Page 273: 85


c. 640 kilometers per hour.

Work Step by Step

As we know that velocity of tsunami for depth d is $v=\sqrt{gd}=450\frac{Km}{h}$ so velocity of tsunami for depth 2d is $v^{\prime}=\sqrt{2gd}$ $\implies v^{\prime}=\sqrt{2} \space gd$ $\implies v^{\prime}=\sqrt{2}\times 450\approx 640\frac{Km}{h}$
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