Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 14 - Exercises and Problems - Page 273: 76


$.0153 \ m/s$

Work Step by Step

We use equation 14.16, which involves a Doppler shift for a moving observer, to find: $f'=f(1\pm\frac{u}{v})$ Considering the second shift, this equation becomes: $\Delta f = \frac{2 uf }{v-u}$ We know that the speed of sound in a human body, in this case v in the equation, is $1540 \ m/s$. Thus, we find: $\Delta f v - \Delta f u =2uf$ $\Delta f v = \Delta f u +2uf$ $\Delta f v =u( \Delta f +2f)$ $u = \frac{\Delta f v }{\Delta f +2f}$ $u = \frac{(100)(1540)}{ 100 +2(5,000,000)}=.0153 \ m/s$
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