Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 13 - Exercises and Problems - Page 246: 45

Answer

70.7 minutes

Work Step by Step

We first must find the period of an oscillation: $ T = 2\pi \sqrt{\frac{2L}{3g}}= 2\pi \sqrt{\frac{2(.188)}{3(9.81)}}=.710\ s$ We multiply this by the number of oscillations to find: $t = .710\ s \times 5974 = 4242.72 \ s = \fbox{70.7 minutes}$
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