Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 12 - Exercises and Problems - Page 221: 15

Answer

Please see the work below.

Work Step by Step

We know that the torque about the rigid end of the log is given as $mgx_{cm}-Td=0$ We plug in the known values to obtain: $(7.5)x_m-(6.2)(23-4)=0$ This simplifies to: $x_{cm}=16m$
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