## Essential University Physics: Volume 1 (4th Edition)

(a)$\tau=(\frac{L}{2})mg$ (b)0 (c)$\tau=(\frac{L}{2})mg$
We know that (a) $\tau=r\times F$ $\implies \tau=(\frac{L}{2})mg$ (b) $\tau=r\times F$ $\implies \tau=(0)mg$ $\tau=0$ (c) $\tau=r\times F$ $\tau=-(\frac{L}{2})mg$