Answer
The torques still sum to zero.
Work Step by Step
Recall that the net torque is equal to the sum of all of the torques, which are each given by $\vec{r}\times\vec{F}$. In addition, recall that the position vector is given by the vector $\vec{r}=x\hat{i}+y\hat{j}$, where x,y are the x and y distances the applied torque is from the axis of rotation, respectively. Doing this, we find that all of the torques still sum to zero.
