## Essential University Physics: Volume 1 (4th Edition)

a) We use the equation for the change in theta to find: $\Delta \theta = \omega_0t + \frac{1}{2}\alpha t^2 \\ \Delta \theta = \frac{1}{2}(.01)(14^2)=.98 \ rads = \fbox{.156 revolutions}$ b) We find: $\bar{\omega}=\frac{\theta}{t}=\frac{.98}{14}=\fbox{.07 radians per second}$