Essential University Physics: Volume 1 (4th Edition)

We use the equation for angular speed, which is $\omega = \frac{2\pi}{\Delta t}$, to find: a) $\omega=\frac{2\pi}{86400}=7.27\times10^{-5}$ b) $\omega=\frac{2\pi}{s3600}=.0017$ c) $\omega=\frac{2\pi}{12\times3600}=1.45\times10^{-4}$ d) $\omega=\frac{2\pi}{.205}=30.7$