Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 10 - Exercises and Problems - Page 191: 16

Answer

a) 725 seconds b) 21,749 revolutions

Work Step by Step

a) Converting rotations per minute into radians per second and then using the correct equation, we obtain: $\omega = \omega_0 +\alpha t \\377 = 0+.52t \\ t = \fbox{725 seconds}$ b) We find the change in theta: $\theta=\omega_0 t +\frac{1}{2}\alpha t^2 \\ \theta = \frac{1}{2}(.52)(725^2)=1.4\times10^5 \ rads = \fbox{21,749 revolutions}$
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