## Introductory Chemistry (5th Edition)

a) $32^{\circ}F$ is the missing blank. b) $-40^{\circ}C$ is the missing Celsius blank and $233.15 K$ is the missing Kelvin blank. c) $233.33^{\circ}F$ is the missing blank for Fahrenheit and $111.85^{\circ} C$ is the missing blank for the Celsius temperature.
a) For part a) to fill in one of the three blanks we only need to use one of the conversion factors as the other one will give the same answer. So to find the missing Fahrenheit temperature we can convert from Celsius. using the following formula $(^{\circ}C\times\frac{9}{5})+32$, therefore $(0^{\circ}C\times\frac{9}{5})+32 = 32^{\circ}F$ b) To find the missing Celsius temperature we can convert from Fahrenheit using the following formula $(^{\circ}F-32)\times\frac{5}{9}$, therefore $(-40^{\circ}F-32)\times\frac{5}{9} = -40^{\circ}C$. To find the other blank for Kelvin, we can use our Celsius temperature and simply add $273.15$. Therefore, $-40^{\circ}C + 273.15 = 233.15 K$ c) To find the missing Celsius temperature we can convert from Kelvin by simply subtracting $273.15$ so therefore $385 K - 273.15 = 111.85^{\circ}C$ and now to find the missing Fahrenheit temperature we can convert from Celsius, using the following formula $(^{\circ}C\times\frac{9}{5})+32$, therefore $(111.85^{\circ}C\times\frac{9}{5})+32 = 233.33^{\circ}F$