Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 3 - Matter and Energy - Exercises - Problems - Page 89: 72

Answer

$-43.89^{\circ}C$ $229.261 K$

Work Step by Step

Use the formula $(^{\circ}F-32) \times\frac{5}{9}$ to convert from Fahrenheit to Celsius and to convert from Fahrenheit to Kelvin, simply add 273.15 from the Celsius temperature. $(-47^{\circ}F - 32) \times\frac{9}{5} = -43.89^{\circ}C$ $(-47^{\circ}F - 32) \times\frac{9}{5} + 273.15 = 229.261 K$
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