Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 3 - Matter and Energy - Exercises - Problems - Page 89: 70


$-452.11^{\circ}F$ $-268.95^{\circ}C$

Work Step by Step

Use the formula $(Kelvin - 273.15) \times\frac{9}{5}+32$ to convert from Kelvin to Fahrenheit and to convert from Kelvin to Celsius, simply subtract 273.15 from the Kelvin temperature. $(4.2 Kelvin - 273.15) \times\frac{9}{5}+32 = -452.11^{\circ}F$ $(4.2 Kelvin- 273.15)=-268.95^{\circ}C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.