Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 14 - Acids and Bases - Exercises - Problems - Page 524: 82

Answer

(a) $pOH = 4.92$ (b) $pOH = 7.20$ (c) $pOH = 12.86$ (d) $pOH = 3.365$

Work Step by Step

1. Calculate the pOH Value $pH = -log[H_3O^+]$ $pH = -log( 8.3 \times 10^{- 10})$ $pH = 9.08$ $pOH + pH = 14$ $pOH = 14 - pH = 14 - 9.08$ $pOH = 4.92$ 2. Calculate the pOH Value $pH = -log[H_3O^+]$ $pH = -log( 1.6 \times 10^{- 7})$ $pH = 6.80$ $pOH + pH = 14$ $pOH = 14 - pH = 14 - 6.80$ $pOH = 7.20$ 3. Calculate the pOH Value $pH = -log[H_3O^+]$ $pH = -log( 0.073)$ $pH = 1.14$ $pOH + pH = 14$ $pOH = 14 - pH = 14 - 1.14$ $pOH = 12.86$ 4. Calculate the pOH value: $pOH = -log[OH^-]$ $pOH = -log(4.32 \times 10^{-4})$ $pOH = 3.365$
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