## Introductory Chemistry (5th Edition)

(a) $pOH = 6.08$ (b) $pOH = 12.74$ (c) $pOH = 5.59$ (d) $pOH = 1.274$
1. Calculate the pOH Value $pH = -log[H_3O^+]$ $pH = -log( 1.2 \times 10^{- 8})$ $pH = 7.92$ $pOH + pH = 14$ $pOH = 14 - pH = 14 - 7.92$ $pOH = 6.08$ 2. Calculate the pOH Value $pH = -log[H_3O^+]$ $pH = -log( 0.055)$ $pH = 1.26$ $pOH + pH = 14$ $pOH = 14 - pH = 14 - 1.26$ $pOH = 12.74$ 3. Calculate the pOH Value $pH = -log[H_3O^+]$ $pH = -log( 3.9 \times 10^{- 9})$ $pH = 8.41$ $pOH + pH = 14$ $pOH = 14 - pH = 14 - 8.41$ $pOH = 5.59$ 4. Calculate the pOH Value $pH = -log[H_3O^+]$ $pH = -log( 1.88 \times 10^{- 13})$ $pH = 12.726$ $pOH + pH = 14$ $pOH = 14 - pH = 14 - 12.726$ $pOH = 1.274$