Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 14 - Acids and Bases - Exercises - Problems - Page 524: 79

Answer

(a) $pOH = 8.82$: Acidic solution. (b) $pOH = 4.15$: Basic solution. (c) $pOH = 7.00$: Neutral solution (d) $pOH = 2.06$: Basic solution.

Work Step by Step

pOH < 7: Basic solution pOH = 7: Neutral solution pOH > 7: Acidic solution. 1. Calculate the pOH value: $pOH = -log[OH^-]$ $pOH = -log(1.5 \times 10^{-9})$ pOH = 8.82 2. Calculate the pOH value: $pOH = -log[OH^-]$ $pOH = -log(7 \times 10^{-5})$ pOH = 4.15 3. Calculate the pOH value: $pOH = -log[OH^-]$ $pOH = -log(10 \times 10^{-8})$ pOH = 7 4. Calculate the pOH value: $pOH = -log[OH^-]$ $pOH = -log(8.8 \times 10^{-3})$ pOH = 2.06
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