Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 14 - Acids and Bases - Exercises - Problems - Page 523: 76

Answer

(a) $[OH^-] = 6.6 \times 10^{- 13}M$ (b) $[OH^-] = 1.9 \times 10^{- 1}M$ (c) $[OH^-] = 1.9 \times 10^{- 6}M$ (d) $[OH^-] = 2.1 \times 10^{- 12}M$

Work Step by Step

1. Calculate the hydroxide ion concentration: pH + pOH = 14 1.82 + pOH = 14 pOH = 12.18 $[OH^-] = 10^{-pOH}$ $[OH^-] = 10^{- 12.18}$ $[OH^-] = 6.6 \times 10^{- 13}M$ 2. Calculate the hydroxide ion concentration: pH + pOH = 14 13.28 + pOH = 14 pOH = 0.72 $[OH^-] = 10^{-pOH}$ $[OH^-] = 10^{- 0.72}$ $[OH^-] = 1.9 \times 10^{- 1}$ 3. Calculate the hydroxide ion concentration: pH + pOH = 14 8.29 + pOH = 14 pOH = 5.71 $[OH^-] = 10^{-pOH}$ $[OH^-] = 10^{- 5.71}$ $[OH^-] = 1.9 \times 10^{- 6}M$ 4. Calculate the hydroxide ion concentration: pH + pOH = 14 2.32 + pOH = 14 pOH = 11.68 $[OH^-] = 10^{-pOH}$ $[OH^-] = 10^{- 11.68}$ $[OH^-] = 2.1 \times 10^{- 12}M$
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