Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 14 - Acids and Bases - Exercises - Problems - Page 523: 74

Answer

(a) $pH = 3.45$ (b) $pH = 11.98$ (c) $pH = 2.58$ (d) $pH = 10.81$

Work Step by Step

1. Calculate the pOH: $pOH = -log[OH^-]$ $pOH = -log( 2.8 \times 10^{- 11})$ $pOH = 10.55$ 2. Find the pH: $pH + pOH = 14$ $pH + 10.55 = 14$ $pH = 3.45$ 3. Calculate the pOH: $pOH = -log[OH^-]$ $pOH = -log( 9.6 \times 10^{- 3})$ $pOH = 2.02$ 4. Find the pH: $pH + pOH = 14$ $pH + 2.02 = 14$ $pH = 11.98$ 5. Calculate the pOH: $pOH = -log[OH^-]$ $pOH = -log( 3.8 \times 10^{- 12})$ $pOH = 11.42$ 6. Find the pH: $pH + pOH = 14$ $pH + 11.42 = 14$ $pH = 2.58$ 7. Calculate the pOH: $pOH = -log[OH^-]$ $pOH = -log( 6.4 \times 10^{- 4})$ $pOH = 3.19$ 8. Find the pH: $pH + pOH = 14$ $pH + 3.19 = 14$ $pH = 10.81$
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