Answer
The $Cl^-$ concentration, in milliequivalents per liter is equal to 155 mEq/L
Work Step by Step
The sum of the equivalents of all the negative ions must be equal to the same of the positive ion(s).
For this solution:
$$mEq \space (Cl^-) = mEq \space (Na^+) + mEq \space (K^+) + mEq \space (Ca^{2+})$$
$$mEq \space (Cl^-)= 147 \space mEq + 4 \space mEq + 4 \space mEq$$ $$mEq \space (Cl^-) = 155 \space mEq$$
Therefore, there are 155 mEq of $Cl^-$ per liter of solution.