Answer
a. 1 Eq $K^+$
b. 2 Eq $OH^-$
c. 2 Eq $Ca^{2+}$
d. 6 Eq $C{O_3}^{2-}$
Work Step by Step
1. Identify the absolute value of the charge of each ion.
a. 1
b. 1
c. 2
d. 2
2.
1 mole of each compound is equal to "x" Eq of the same compound. In this case, for ions, x is equal to the absolute value of the charge in each ion.
a. $1 \space mole \space K^+ = 1 \space Eq \space K^+$
b. $1 \space mole \space OH^- = 1 \space Eq \space OH^-$
c. $1 \space mole \space Ca^{2+} = 2 \space Eq \space Ca^{2+}$
d. $1 \space mole \space C{O_3}^{2-} = 2 \space Eq \space C{O_3}^{2-}$
3. Use these as conversion factors:
a. $$1 \space moles \space K^+ \times \frac{1 \space Eq \space K^+}{1 \space mole \space K^+} = 1 \space Eq \space K^+$$
b. $$2 \space moles \space OH^- \times \frac{1 \space Eq \space OH^-}{1 \space mole \space OH^-} = 2 \space Eq \space OH^-$$
c. $$1 \space moles \space Ca^{2+} \times \frac{2 \space Eq \space Ca^{2+}}{1 \space mole \space Ca^{2+}} = 2 \space Eq \space Ca^{2+}$$
d. $$3 \space moles \space C{O_3}^{2-} \times \frac{2 \space Eq \space C{O_3}^{2-}}{1 \space mole \space C{O_3}^{2-}} = 6 \space Eq \space C{O_3}^{2-}$$
