General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 10 - Reaction Rates and Chemical Equilibrium - Additional Questions and Problems - Page 397: 10.50

Answer

a. $$K_c = \frac{[ SO_3 ]^{ 2 }}{[ SO_2 ]^{ 2 }[ O_2 ]}$$ b. $K_c = 3.0 \times 10^2$

Work Step by Step

1. Write the equilibrium constant expression: $$K_c = \frac{[Products]}{[Reactants]} = \frac{[ SO_3 ]^{ 2 }}{[ SO_2 ]^{ 2 }[ O_2 ]}$$ 2. Substitute the values and calculate the constant value: $$K_c = \frac{( 0.60 )^{ 2 }}{( 0.10 )^{ 2 }( 0.12 )} = 3.0 \times 10^2$$
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