Answer
$$[CH_3OH] = 0.24 \space M$$
Work Step by Step
1. Write the equilibrium constant expression:
$$K_c = \frac{[Products]}{[Reactants]} = \frac{[ CH_3OH ]}{[ CO ][ H_2 ]^{ 2 }}$$
2. Solve for the missing concentration:
$$K_c \times [ CO ][ H_2 ]^{ 2 } = [CH_3OH]$$
3. Evaluate the expression:
$$ [CH_3OH] = { 15 \times ( 0.40 )( 0.20 )^{ 2 }}$$
$$[CH_3OH] = 0.24 \space M$$
