## General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

The molar concentration of $N_2O_4$ is equal to $1.3 \space M$
1. Write the equilibrium constant expression: $$K_c = \frac{[Products]}{[Reactants]} = \frac{[ N_2O_4 ]}{[ NO_2 ]^{ 2 }}$$ 2. Solve for the missing concentration: $$K_c \times [ NO_2 ]^{ 2 } = [N_2O_4]$$ 3. Evaluate the expression: $$[N_2O_4] = { 5.0 \times ( 0.50 )^{ 2 }{}}$$ $$[N_2O_4] = 1.3 \space M$$