## General Chemistry (4th Edition)

$pH = 13.30$ This is a basic solution.
1. Since $CsOH$ is a strong base: $Initial[CsOH] = [OH^-] = 0.20M$: 2. Now, calculate the pH. $pOH = -log[OH^-]$ $pOH = -log( 0.20)$ $pOH = 0.70$ $pH + pOH = 14$ $pH + 0.70 = 14$ $pH = 13.30$ 3. At $25^{\circ}C$: $pH > 7$: basic solution.