## General Chemistry (4th Edition)

$[OH^-] = 1 \times 10^{- 3}M$
1. Calculate the pOH: pH + pOH = 14 11 + pOH = 14 pOH = 3 2. Use this value to calculate the hydroxide concentration: $[OH^-] = 10^{-pOH}$ $[OH^-] = 10^{- 3}$ $[OH^-] = 1 \times 10^{- 3}$