## General Chemistry (4th Edition)

$[H_3O^+] = 1.585 \times 10^{- 7}M$
We use the pH to find: $[H_3O^+] = 10^{-pH}$ $[H_3O^+] = 10^{- 6.8}$ $[H_3O^+] = 1.585 \times 10^{- 7}M$