## General Chemistry (4th Edition)

$15.33$ metric tons
By the given condition of the ratio, we have $0.652\cdot\text{ore}=\text{titanium}$, so in order to obtain $10000\text{ kg}$ of titanium, we need $$\frac{10\text{ tons}}{0.652}=15.33\text{ tons}$$ of its ore.