General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 2 Atoms and Molecules - Problems - Page 76: 75


$15.33$ metric tons

Work Step by Step

By the given condition of the ratio, we have $0.652\cdot\text{ore}=\text{titanium}$, so in order to obtain $10000\text{ kg}$ of titanium, we need $$\frac{10\text{ tons}}{0.652}=15.33\text{ tons}$$ of its ore.
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