General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 17 Chemical Kinetics: Rate Laws - Problems - Page 638: 6

Answer

Rate of reaction$=3.5×10^{−14}M.min^{−1}$ Third-order reaction

Work Step by Step

The rate of the reaction is equal to: Rate of reaction$=1.3×10^{-3}M^{−2}.min^{−1}[NO]^{2}[Br_2]$ $[NO]=3.0×10^{−4}M$ $[Br_2]=3.0×10^{−4}M$ Rate of reaction$=1.3×10^{-3}M^{−2}.min^{−1}\times(3.0×10^{−4}M)^2\times3.0×10^{−4}M=3.5×10^{−14}M.min^{−1}$ The order of the reaction is equal to: $[NO]^{2}[Br_2]^{1}=2+1=3$ Third-order reaction
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