General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 17 Chemical Kinetics: Rate Laws - Problems - Page 638: 1

Answer

Rate of reaction=$-\frac{1}{2}(\frac{[NOCl]}{\Delta t})$ Rate of reaction=$\frac{1}{2}(\frac{[NO]}{\Delta t})$ Rate of reaction=$\frac{1}{1}(\frac{[Cl_2]}{\Delta t})=\frac{[Cl_2]}{\Delta t}$

Work Step by Step

For the general equation: $aA+bB\rightarrow cC+dD$ The rate of reaction is equal to: Rate of reaction=$-\frac{1}{a}(\frac{[A]}{\Delta t})$ Rate of reaction=$-\frac{1}{b}(\frac{[B]}{\Delta t})$ Rate of reaction=$\frac{1}{c}(\frac{[C]}{\Delta t})$ Rate of reaction=$\frac{1}{d}(\frac{[D]}{\Delta t})$ So, the rate of reaction: $2NOCl\rightarrow2NO+Cl_2$ Rate of reaction=$-\frac{1}{2}(\frac{[NOCl]}{\Delta t})$ Rate of reaction=$\frac{1}{2}(\frac{[NO]}{\Delta t})$ Rate of reaction=$\frac{1}{1}(\frac{[Cl_2]}{\Delta t})=\frac{[Cl_2]}{\Delta t}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.