Answer
Rate of reaction=$-\frac{1}{2}(\frac{[NOCl]}{\Delta t})$
Rate of reaction=$\frac{1}{2}(\frac{[NO]}{\Delta t})$
Rate of reaction=$\frac{1}{1}(\frac{[Cl_2]}{\Delta t})=\frac{[Cl_2]}{\Delta t}$
Work Step by Step
For the general equation:
$aA+bB\rightarrow cC+dD$
The rate of reaction is equal to:
Rate of reaction=$-\frac{1}{a}(\frac{[A]}{\Delta t})$
Rate of reaction=$-\frac{1}{b}(\frac{[B]}{\Delta t})$
Rate of reaction=$\frac{1}{c}(\frac{[C]}{\Delta t})$
Rate of reaction=$\frac{1}{d}(\frac{[D]}{\Delta t})$
So, the rate of reaction:
$2NOCl\rightarrow2NO+Cl_2$
Rate of reaction=$-\frac{1}{2}(\frac{[NOCl]}{\Delta t})$
Rate of reaction=$\frac{1}{2}(\frac{[NO]}{\Delta t})$
Rate of reaction=$\frac{1}{1}(\frac{[Cl_2]}{\Delta t})=\frac{[Cl_2]}{\Delta t}$