Answer
Rate of reaction=$-\frac{1}{2}(\frac{[SO_2]}{\Delta t})$
Rate of reaction=$-\frac{1}{1}(\frac{[O_2]}{\Delta t})=-\frac{[O_2]}{\Delta t}$
Rate of reaction=$\frac{1}{2}(\frac{[SO_3]}{\Delta t})$
Work Step by Step
For the general equation:
$aA+bB\rightarrow cC+dD$
The rate of reaction is equal to:
Rate of reaction=$-\frac{1}{a}(\frac{[A]}{\Delta t})$
Rate of reaction=$-\frac{1}{b}(\frac{[B]}{\Delta t})$
Rate of reaction=$\frac{1}{c}(\frac{[C]}{\Delta t})$
Rate of reaction=$\frac{1}{d}(\frac{[D]}{\Delta t})$
So, the rate of reaction:
$2SO_2+O_2\rightarrow2SO_3$
Rate of reaction=$-\frac{1}{2}(\frac{[SO_2]}{\Delta t})$
Rate of reaction=$-\frac{1}{1}(\frac{[O_2]}{\Delta t})=-\frac{[O_2]}{\Delta t}$
Rate of reaction=$\frac{1}{2}(\frac{[SO_3]}{\Delta t})$
