General Chemistry (4th Edition)

Published by University Science Books

Chapter 1 Chemistry and the Scientific Method - Problems - Page 35: 28

Answer

$0.599\%$

Work Step by Step

The average density of mercury at $35^{\ \circ}C$ based on the measurement results is: $$\frac{13.56\text{ g}\cdot\text{cm}^{-3}+13.62\text{ g}\cdot\text{cm}^{-3}+13.59\text{ g}\cdot\text{cm}^{-3}}{3}=13.59\text{ g}\cdot\text{cm}^{-3}$$ The true density of mercury at $35^{\ \circ}C$ is $13.509\text{ g}\cdot\text{cm}^{-3}$; thus: $$\text{percentage error}=\frac{13.59\text{ g}\cdot\text{cm}^{-3}-13.509\text{ g}\cdot\text{cm}^{-3}}{13.509\text{ g}\cdot\text{cm}^{-3}}\cdot 100=0.599\%$$ (Note, percent error is always a positive quantity, so if the equation gives a negative value, the value should be changed to a positive value.)

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